Integrand size = 27, antiderivative size = 129 \[ \int \cot ^7(c+d x) \csc ^8(c+d x) (a+a \sin (c+d x)) \, dx=\frac {a \csc ^7(c+d x)}{7 d}+\frac {a \csc ^8(c+d x)}{8 d}-\frac {a \csc ^9(c+d x)}{3 d}-\frac {3 a \csc ^{10}(c+d x)}{10 d}+\frac {3 a \csc ^{11}(c+d x)}{11 d}+\frac {a \csc ^{12}(c+d x)}{4 d}-\frac {a \csc ^{13}(c+d x)}{13 d}-\frac {a \csc ^{14}(c+d x)}{14 d} \]
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Time = 0.07 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {2915, 12, 90} \[ \int \cot ^7(c+d x) \csc ^8(c+d x) (a+a \sin (c+d x)) \, dx=-\frac {a \csc ^{14}(c+d x)}{14 d}-\frac {a \csc ^{13}(c+d x)}{13 d}+\frac {a \csc ^{12}(c+d x)}{4 d}+\frac {3 a \csc ^{11}(c+d x)}{11 d}-\frac {3 a \csc ^{10}(c+d x)}{10 d}-\frac {a \csc ^9(c+d x)}{3 d}+\frac {a \csc ^8(c+d x)}{8 d}+\frac {a \csc ^7(c+d x)}{7 d} \]
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Rule 12
Rule 90
Rule 2915
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {a^{15} (a-x)^3 (a+x)^4}{x^{15}} \, dx,x,a \sin (c+d x)\right )}{a^7 d} \\ & = \frac {a^8 \text {Subst}\left (\int \frac {(a-x)^3 (a+x)^4}{x^{15}} \, dx,x,a \sin (c+d x)\right )}{d} \\ & = \frac {a^8 \text {Subst}\left (\int \left (\frac {a^7}{x^{15}}+\frac {a^6}{x^{14}}-\frac {3 a^5}{x^{13}}-\frac {3 a^4}{x^{12}}+\frac {3 a^3}{x^{11}}+\frac {3 a^2}{x^{10}}-\frac {a}{x^9}-\frac {1}{x^8}\right ) \, dx,x,a \sin (c+d x)\right )}{d} \\ & = \frac {a \csc ^7(c+d x)}{7 d}+\frac {a \csc ^8(c+d x)}{8 d}-\frac {a \csc ^9(c+d x)}{3 d}-\frac {3 a \csc ^{10}(c+d x)}{10 d}+\frac {3 a \csc ^{11}(c+d x)}{11 d}+\frac {a \csc ^{12}(c+d x)}{4 d}-\frac {a \csc ^{13}(c+d x)}{13 d}-\frac {a \csc ^{14}(c+d x)}{14 d} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 129, normalized size of antiderivative = 1.00 \[ \int \cot ^7(c+d x) \csc ^8(c+d x) (a+a \sin (c+d x)) \, dx=\frac {a \csc ^7(c+d x)}{7 d}+\frac {a \csc ^8(c+d x)}{8 d}-\frac {a \csc ^9(c+d x)}{3 d}-\frac {3 a \csc ^{10}(c+d x)}{10 d}+\frac {3 a \csc ^{11}(c+d x)}{11 d}+\frac {a \csc ^{12}(c+d x)}{4 d}-\frac {a \csc ^{13}(c+d x)}{13 d}-\frac {a \csc ^{14}(c+d x)}{14 d} \]
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Time = 0.60 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.68
method | result | size |
derivativedivides | \(-\frac {a \left (\frac {\left (\csc ^{14}\left (d x +c \right )\right )}{14}+\frac {\left (\csc ^{13}\left (d x +c \right )\right )}{13}-\frac {\left (\csc ^{12}\left (d x +c \right )\right )}{4}-\frac {3 \left (\csc ^{11}\left (d x +c \right )\right )}{11}+\frac {3 \left (\csc ^{10}\left (d x +c \right )\right )}{10}+\frac {\left (\csc ^{9}\left (d x +c \right )\right )}{3}-\frac {\left (\csc ^{8}\left (d x +c \right )\right )}{8}-\frac {\left (\csc ^{7}\left (d x +c \right )\right )}{7}\right )}{d}\) | \(88\) |
default | \(-\frac {a \left (\frac {\left (\csc ^{14}\left (d x +c \right )\right )}{14}+\frac {\left (\csc ^{13}\left (d x +c \right )\right )}{13}-\frac {\left (\csc ^{12}\left (d x +c \right )\right )}{4}-\frac {3 \left (\csc ^{11}\left (d x +c \right )\right )}{11}+\frac {3 \left (\csc ^{10}\left (d x +c \right )\right )}{10}+\frac {\left (\csc ^{9}\left (d x +c \right )\right )}{3}-\frac {\left (\csc ^{8}\left (d x +c \right )\right )}{8}-\frac {\left (\csc ^{7}\left (d x +c \right )\right )}{7}\right )}{d}\) | \(88\) |
risch | \(-\frac {32 i a \left (15015 i {\mathrm e}^{20 i \left (d x +c \right )}+8580 \,{\mathrm e}^{21 i \left (d x +c \right )}+54054 i {\mathrm e}^{18 i \left (d x +c \right )}+20020 \,{\mathrm e}^{19 i \left (d x +c \right )}+129129 i {\mathrm e}^{16 i \left (d x +c \right )}+41860 \,{\mathrm e}^{17 i \left (d x +c \right )}+152724 i {\mathrm e}^{14 i \left (d x +c \right )}+9940 \,{\mathrm e}^{15 i \left (d x +c \right )}+129129 i {\mathrm e}^{12 i \left (d x +c \right )}-9940 \,{\mathrm e}^{13 i \left (d x +c \right )}+54054 i {\mathrm e}^{10 i \left (d x +c \right )}-41860 \,{\mathrm e}^{11 i \left (d x +c \right )}+15015 i {\mathrm e}^{8 i \left (d x +c \right )}-20020 \,{\mathrm e}^{9 i \left (d x +c \right )}-8580 \,{\mathrm e}^{7 i \left (d x +c \right )}\right )}{15015 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{14}}\) | \(194\) |
parallelrisch | \(-\frac {\left (\tan ^{28}\left (\frac {d x}{2}+\frac {c}{2}\right )+\frac {28 \left (\tan ^{27}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{13}-\frac {28 \left (\tan ^{25}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{11}-\frac {49 \left (\tan ^{24}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}-\frac {56 \left (\tan ^{23}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}+24 \left (\tan ^{21}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+49 \left (\tan ^{20}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+84 \left (\tan ^{19}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-140 \left (\tan ^{17}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-245 \left (\tan ^{16}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-560 \left (\tan ^{15}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-560 \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-245 \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-140 \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+84 \left (\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+49 \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+24 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\frac {56 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}-\frac {49 \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}-\frac {28 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{11}+\frac {28 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{13}+1\right ) a}{229376 d \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{14}}\) | \(289\) |
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Time = 0.28 (sec) , antiderivative size = 166, normalized size of antiderivative = 1.29 \[ \int \cot ^7(c+d x) \csc ^8(c+d x) (a+a \sin (c+d x)) \, dx=\frac {15015 \, a \cos \left (d x + c\right )^{6} - 9009 \, a \cos \left (d x + c\right )^{4} + 3003 \, a \cos \left (d x + c\right )^{2} + 40 \, {\left (429 \, a \cos \left (d x + c\right )^{6} - 286 \, a \cos \left (d x + c\right )^{4} + 104 \, a \cos \left (d x + c\right )^{2} - 16 \, a\right )} \sin \left (d x + c\right ) - 429 \, a}{120120 \, {\left (d \cos \left (d x + c\right )^{14} - 7 \, d \cos \left (d x + c\right )^{12} + 21 \, d \cos \left (d x + c\right )^{10} - 35 \, d \cos \left (d x + c\right )^{8} + 35 \, d \cos \left (d x + c\right )^{6} - 21 \, d \cos \left (d x + c\right )^{4} + 7 \, d \cos \left (d x + c\right )^{2} - d\right )}} \]
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Timed out. \[ \int \cot ^7(c+d x) \csc ^8(c+d x) (a+a \sin (c+d x)) \, dx=\text {Timed out} \]
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Time = 0.21 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.71 \[ \int \cot ^7(c+d x) \csc ^8(c+d x) (a+a \sin (c+d x)) \, dx=\frac {17160 \, a \sin \left (d x + c\right )^{7} + 15015 \, a \sin \left (d x + c\right )^{6} - 40040 \, a \sin \left (d x + c\right )^{5} - 36036 \, a \sin \left (d x + c\right )^{4} + 32760 \, a \sin \left (d x + c\right )^{3} + 30030 \, a \sin \left (d x + c\right )^{2} - 9240 \, a \sin \left (d x + c\right ) - 8580 \, a}{120120 \, d \sin \left (d x + c\right )^{14}} \]
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Time = 0.40 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.71 \[ \int \cot ^7(c+d x) \csc ^8(c+d x) (a+a \sin (c+d x)) \, dx=\frac {17160 \, a \sin \left (d x + c\right )^{7} + 15015 \, a \sin \left (d x + c\right )^{6} - 40040 \, a \sin \left (d x + c\right )^{5} - 36036 \, a \sin \left (d x + c\right )^{4} + 32760 \, a \sin \left (d x + c\right )^{3} + 30030 \, a \sin \left (d x + c\right )^{2} - 9240 \, a \sin \left (d x + c\right ) - 8580 \, a}{120120 \, d \sin \left (d x + c\right )^{14}} \]
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Time = 9.96 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.71 \[ \int \cot ^7(c+d x) \csc ^8(c+d x) (a+a \sin (c+d x)) \, dx=-\frac {-\frac {a\,{\sin \left (c+d\,x\right )}^7}{7}-\frac {a\,{\sin \left (c+d\,x\right )}^6}{8}+\frac {a\,{\sin \left (c+d\,x\right )}^5}{3}+\frac {3\,a\,{\sin \left (c+d\,x\right )}^4}{10}-\frac {3\,a\,{\sin \left (c+d\,x\right )}^3}{11}-\frac {a\,{\sin \left (c+d\,x\right )}^2}{4}+\frac {a\,\sin \left (c+d\,x\right )}{13}+\frac {a}{14}}{d\,{\sin \left (c+d\,x\right )}^{14}} \]
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